91262-sam-2012.doc | |
File Size: | 439 kb |
File Type: | doc |
91262-sas-2012.doc | |
File Size: | 118 kb |
File Type: | doc |
Calculus
Remember that we differentiate to find the gradient function.
When we have the gradient function, we can substitute in an x value to find the gradient at that point. This is also the gradient of the tangent at that point.
To find the equation of the tangent, first we need a coordinate. Substitute the required x-value into the original equation to find a y-value [y=f(x))].
If we then call this coordinate (h,v) [for horizontal=x and vertical=y ordinates]
Then use m=gradient=f'(h)
Then sub into y=m(x-h) +v [where m, h and v are the numbers you just found.]
Remember that we differentiate to find the gradient function.
When we have the gradient function, we can substitute in an x value to find the gradient at that point. This is also the gradient of the tangent at that point.
To find the equation of the tangent, first we need a coordinate. Substitute the required x-value into the original equation to find a y-value [y=f(x))].
If we then call this coordinate (h,v) [for horizontal=x and vertical=y ordinates]
Then use m=gradient=f'(h)
Then sub into y=m(x-h) +v [where m, h and v are the numbers you just found.]